n^2-3n=132

Solution for n^2-3n=132 equation:

n^2-3n=132

We move all terms to the left:

n^2-3n-(132)=0

a = 1; b = -3; c = -132;
Δ = b2-4ac
Δ = -32-4·1·(-132)
Δ = 537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{537}}{2*1}=\frac{3-\sqrt{537}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{537}}{2*1}=\frac{3+\sqrt{537}}{2}
$